A tree is a connected graph without any circuits
Proof:
Since T is a connected graph, there must exist at least one path between every pair of vertices in T. Now suppose that between two vertices a and b of T there are two distinct paths. The union of these two paths will contain a circuit and T cannot be a tree.
THEOREM 2 : If in a graph G there is one and only one path between every pair of vertices,
G is a tree.
Proof:
Existence of a path between every pair of vertices assures that G is connected. A circuit in a graph (with two or more vertices) implies that there is at least one pair of vertices a, b such that there are two distinct paths between a and b. Since G has one and only one path between every pair of vertices, G can have no circuit. Therefore, G is a tree.
A tree T is said to be a spanning tree of a connected graph G if T is a subgraph of G and T contains all vertices of G.
xij = 1, if there is an edge between ith and jth vertices, and
= 0, if there is no edge between them.
Q: Draw the adjacency matrix of the given graph
Ans: The adjacency matrix is
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