Kay's Math: Matrices-set 2 Practice questions for Business mathematics -Kerala university Bcom

$If A=\begin{matrix} 3&5 \\ 2&a \end{matrix} \\ B=\begin{matrix} 4&b\\ 2&a \end{matrix} \\C=\begin{matrix} 26&a\\14&45\end{matrix}$ find a and b when 2A+5B=C (ICWA 1996)

$A=\begin{matrix} 1&2&2 \\ 2&1&2\\ 2&2&1 \end{matrix} \\$ Show that the given matrix A satisfies the equation $A^{2}-4A-5I=0$

If $A=\begin{matrix} 1&-1\\2&-1\end{matrix} \> \> B=\begin{matrix} x&1\\y&-1\end{matrix} \>and (A+B)^{2}=A^{2}+B^{2} find \> x \>and\> y$

If $A=\begin{matrix} 2&0&-1\\2&4&-1\\1&-8&-3\end{matrix} \> show\>that\> A(adj\>A)=\left |A \right |I_{3}$

$A=\begin{matrix} 0&1\\-1&0 \end{matrix} \: find \>\alpha \>and \> \beta \> such\>that\> (\alpha I+\beta A)^{2}=A$

$A=\begin{matrix} 1&1&-1\\2&0&3\\3&-1&2 \end{matrix} \> B=\begin{matrix}1&3\\0&2\\-1&4 \end{matrix} \> C=\begin{matrix} 1&2&3&4\\2&0&-2&-1\end{matrix} \\ Show \>that\>A(BC)=(AB)C$

$A=\begin{matrix} 1&2&-3\\5&0&2\\1&-1&1 \end{matrix} \> B=\begin{matrix}3&-1&2\\4&2&5\\2&0&3 \end{matrix}\>find\>matrix\>C\>such\>that\>A+C=B$

$A=\begin{matrix} 1&-3&2\\2&1&-3\\4&-3&-1 \end{matrix} \> B=\begin{matrix}1&4&1&0\\2&1&1&1\\1&-2&1&2\end{matrix}\>C=\begin{matrix}2&1&-1&-2\\3&-2&-1&-1\\2&-5&-1&0 \end{matrix}\\show\>that\>AB=AC$

https://ellipticalkoyal.blogspot.com/2019/01/matrices-set-1.html matrices set 1

Kay's Math

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Tuesday, January 8, 2019

Matrices-set 2 Practice questions for Business mathematics -Kerala university Bcom

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