Saturday, October 8, 2016

use Newton’s forward and backward Interpolation formula


1.    Find the value of e1.85 given
e1.7=5.4739, e1.8= 6.0496, e1.9= 6.6859, e2.0=7.3891, e2.1=8.1662, e2.2=9.0250, e2.3= 9.9742.
2.    Find the value of y at x=1.05 from the table given below:
X       1.0    1.1    1.2    1.3    1.4    1.5
Y        .841  .891  .932  .964  .985  1.015

3.    Find  the value of f(1.02) given the following data
X                 f(x)
1.0              1.841
1.1              1.891
1.2              0.932
1.3              0.964
1.4              0.985

4.    Find y at x= 105 from the following data:
X                 y
80               5026
85               5674
90               6362
95               7088
100             7854

5.    Find log π given π=3.14159 and
Log 3.141 = 0.4970679364
Log 3.142=0.4972061807
Log3.143=0.4973443810
Log 3.144=0.4974825374
Log 3.145=0.4976206498
6.    Find y(1.02) given
X                 y
1.00            0.3413
1.05            0.3531
1.10            0.3643
1.15            0.3749
1.20            0.3849

7.    Find the value of y at x= 9
X                 y
2                 94.8
5                 87.9
8                 81.3
11               75.1

8.    From the following table estimate sin 28®24’
Ф                 sin ф
25               0.42262
26               0.43837
27               0.45399
28               0.46947
29               0.48481
30               0.50000

9.    Estimate e-1.9 from the given data
X                 e-x
1.00            0.3679
1.25            0.2865
1.50            0.2231
1.75            0.1738
2.00            0.1353

10.                       Find f(0.5) if f(-1)=202, f(0)=175, f(1)=82 and f(2)=55


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